Thursday, 22 August 2013

Converting values with Arabic numbers

Converting values with Arabic numbers

The problem states "Write a program that accepts a 10-digit telephone
number that may contain one or more alphabetic characters. Display the
corresponding number using numerals...etc" ABC:2 through WXYZ:9
This chapter teaches about loops but I found myself really lost at this
problem. I completed the code but I think it sucks...
My question: Is there a better way to shorten this code up? And I only
figured to use the c# keyword case, is there another way?
EDIT: Arabic as in you could type in 1800WALLTO and it will give you
1800925586
ALSO I am not asking for a code that doesn't work, this does EXACTLY what
I want and asked it to do. I am just asking for any advise or input on how
to make it better. I really wanted to know a way to do it without switch
and case break etc...
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
int x = 0;
char userInput = ' ';
string inputString = "",
outputString = "";
Console.WriteLine("Enter the digits from the phone number");
do
{
userInput = Console.ReadKey(false).KeyChar;
inputString += userInput;
if (Char.IsLetter(userInput))
userInput = userInput.ToString().ToUpper().ToCharArray()[0];
switch (userInput)
{
case '1':
outputString += '1';
x++;
break;
case '2':
case 'A':
case 'B':
case 'C':
outputString += '2';
x++;
break;
case '3':
case 'D':
case 'E':
case 'F':
outputString += '3';
x++;
break;
case '4':
case 'G':
case 'H':
case 'I':
outputString += '4';
x++;
break;
case '5':
case 'J':
case 'K':
case 'L':
outputString += '5';
x++;
break;
case '6':
case 'M':
case 'N':
case 'O':
outputString += '6';
x++;
break;
case '7':
case 'P':
case 'Q':
case 'R':
case 'S':
outputString += '7';
x++;
break;
case '8':
case 'T':
case 'U':
case 'V':
outputString += '8';
x++;
break;
case '9':
case 'W':
case 'X':
case 'Y':
case 'Z':
outputString += '9';
x++;
break;
case '0':
outputString += '0';
x++;
break;
default:
Console.WriteLine("You entered an incorrect value-Try
again");
x--;
break;
}
}
while (x < 10);
Console.WriteLine("\nYou entered {0}", inputString);
Console.WriteLine("Your number is {0}", outputString);
}
}
}

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